(x+y)^2-2x-2y+1=0
(x+y)^2-2(x+y)+1=0
(x+y-1)^2=0
x+y-1=0
x+y=1
(x+y)^2007=1^2007=1
1.若(x+y)^2-2x-2y+1=0,求(x+y)^2007值
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