Question

1）当a=4分之1,b=4时,求代数式a的三次方(-b的三次方)二次方+(-2分之1ab2次方)3次方的值

Answer 1

1)a^3-b^3+(-1/2(ab)^2)^3=(1/4)^3-4^3+(-1/2(1/4*4)&^2)^3=7/8

2)6^n=(2*3)^n=(2*3)^n=2^n*3^n=ab

3)=4^3*(1/4)^3x^(6+2)*y^(3+6)=x^8y^9

4)(3^3)^3*x^6*(1/3)^8=4

3*(x^3)^2=4

x^3=根号三分之二