有规律的,自己仔细看看~
(m+3m5m+7m+.2009m)-(2m+4m+6m.2008m)
1个回答
相关问题
-
(m+3m+5m+7m+.+2009m)-(2m-4m-6m-.-2008m)=?
-
(m+3m+5m+...+2009m)-(2m+4m+6m+...2008m)
-
合并同类项:(m+3m+5m+…+2009m)-(2m+4m+6m+…+2008m)
-
m-2m-3m+4m-5m-6m+7m.2004m=?
-
A=M0∧M3∧M5. ∴┑A=M1∧M2∧M4∧M6∧M7.
-
m-2m-3m+4m-5m-6m+7m-8m-9m+.+2002m-2003m-2004m
-
m²-2m-4=0,则m³-m²-6m+2008=
-
(m+3m+5m+...+2015m)-(2m+4m+6m+...+2014m)=
-
计算:(5/6)m·(4/5)m·(3/4)m·(2/3)m·(6/2)m
-
若m^2+m-1=0,则m^2009+m^2008+m^2007+……+m^2+m+2009的值为多少