lim[x-x^2ln(1+1/x)] (X趋近于无穷大)
1个回答
一样的
分子和分母同时除以x^2化为
{1/x-ln(1+1/x)}/(1/x^2)
={-1/x^2+1/x-1/(x+1)}/[-2/(x^3)]
=(1/2)[1/(1+1/x)]
=1/2
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