(7X^2Y^3-8X^3Y^2Z)除以8X^2Y^2
1个回答
(7X^2Y^3-8X^3Y^2Z)÷(8X^2Y^2)
=X^2Y^2(7Y-8XZ)÷(8X^2Y^2)
=(7Y-8XZ)÷8
=7Y/8-XZ
相关问题
已知3x+2y除以2=2y+z除以3=3z+x除以7,求(x+y+z):(3x+2y)的值
求证x^8+y^8+z^8>=x^3y^2z^2+x^2y^3z^2+x^2y^2z^3
3x+4z=7 2x+3y+z=9 5x+9y+7z=8 2x+y+z=9 x+2y+z=8 x+y+2z=7 三元一次
2x-3y+4z=2 4x+y+7z=3 8x+2y+3z=-5
(1)3x+4y=15 2y-z=2 x+2z=9 (2) x+y+z=8 2x+3y-z=6 3x-y+z=8 (3)
2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X
解放程x+y-z=4,2x-y+x=5,x-3y+x=-2 3x-2y=8,2y+3z=1,x+5z=7
解三元一次方程:x+4y+3z=8,4x+y+2z=7,2x+2y-7z=-3
解三元一次方程:x+4y+3z=8,4x+y+2z=7,2x+2y-7z=-3
{x+2y+z=8,2x-y-z=-3,3x+y-2z=-1