根据题计算得知X=1,Y=1
2x²+2xy+y²-6x-4y+5=o
5个回答
相关问题
-
已知x^2+y^2-4x+6y+13=0求(xy+y^2/5x^2-5xy+xy+y^2)·（5/x+y）-（y/x-y
-
2x^2-xy-y^2-4x-5y-6
-
x/3y=y/2x-5y=6x-15y/x,求(4x^2-5xy+6y^2)/(x^2-2xy+3y^2)的值
-
2x^2-3xy+6y^2-x^2+4xy-5y^2
-
5x^3y*(-3y)^2+(-6xy)^2*(-xy)+xy^3*(-4x^2)
-
3x^y(-4xy^)+5xy*(-6xy)^,其中x=2 y=-1/2
-
因式分解2x²+xy-y²-4x+5y-6
-
因式分解2x²+xy-y²-4x+5y-6
-
6x2y+2xy-8x2y-4x-5xy-2x2y2-6x2y化简,x=1,y=2,求值
-
计算5x^3y*(-3y)^2+(-6xy)^2*(-xy)-xy^3(-4x)^2