Question

y=3-2x/x-1的单调区间

Answer 1

y = [3 - 2(x-1+1)]/ (x-1)

= [3-2(x-1)-2]/(x-1)

=[1-2(x-1)]/(x-1)

=1/(x-1) - 2

当x0, 1/(x-1)是反比例函数的右侧,单调递减

所以,单调递增区间(-∞,1)

单调递减区间(1,+∞)