分式的加减(x+3/X^2-9 +x/6+x-x^ - 知识问答

分式的加减(x+3/X^2-9 +x/6+x-x^2)•3-X/4X-6

1个回答

原式=[(x+3)/(x+3)(x-3)-x/(x-3)(x+2)][(3-x)/(4x-6)]
=[1/(x-3)-x/(x-3)(x+2)][(3-x)/(4x-6)]
={[(x+2)-x]/(x-3)(x+2)}[-(x-3)/(4x-6)]
=-[2/(x-3)(x+2)][(x-3)/2(2x-3)]
=-1/(x+2)(2x-3)
=-1/(2x²+x-6)

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