已知(x +y)^2-2x-2y -1=0 则(x +y)^999
2个回答
估计你是抄错了,常数项可能是+1.
(x +y)^2-2x-2y +1=0
(x +y)^2-2(x+y) +1=0
(x +y-1)^2=0
x +y-1=0
x+y=1
(x +y)^999
=1
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