Question

fx=cosx(sinx-根号3cosx)+1怎么化?

Answer 1

f(x)=cosxsinx-√3cos²x+1

=(sin2x)/2-√3(cos2x+1)/2+1

=(1/2)×sin2x-(√3/2)×cos2x-√3/2+1

=sin(2x-π/3)＋(1-√3/2)

类似的题目都可以这样化简

asinx+bcosx

=√(a²+b²)sin(x＋α)

其中,tanα=b/a