-2ab(3a^2-2ab-4b^2) (2b-a

-2ab(3a^2-2ab-4b^2) (2b-a)b-（2a-b）a

1个回答

由（a+b）（a2-ab+b2）=a3-a2b+ab2+a2b-ab2+b=a3+b3，即（a+b）（a2-ab+b2）
{ab-[3a^2b-(4a^2b+1/2ab)]-4a^2b}+3a^2b}=
若a-b=4,ab=1,求(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)
求化简 (a-b)/(a+2b)除以(a^2-b^2)/(a^2+4ab+b^2)-(3a^2-4ab)/(a^2+ab
化简[(a-b)/(a+2b)]/[(a^2-b^2)/(a^2+4ab+b^2)]-(3a^2-4ab)/(a^2+a
3a²b-[2a²b-﹙2ab-a²b﹚-4a²]-ab其中a=3.b=-2
3a^2-(4a^2b-2ab^2-b^2)-(2ab^2+3a^2-3b^2)+3a^2b
化简ab-[3a^2b-(2/3ab+4a^2b)]-(2ab+a^2b)
化简ab-[3a^2b-(2/3ab+4a^2b)]-(2ab+a^2b)
a^2-4b^2=0,(a^2-3ab+b^2)/(ab-a^2+b^2)=?