1设AB=x
则AD=CD=x/4
AC=BC=x/2
BD=3x/4
列式得 x+3x/4+2(x/4+x/2)=26
解得x=8
AC=x/2=4
∵AD=DC;EM+MB.
∴(AD+DC)+CE+(EM+MB)=2DC+CE+2EM.
即AB=2(DC+CE+EM)-CE=2a-b.
1设AB=x
则AD=CD=x/4
AC=BC=x/2
BD=3x/4
列式得 x+3x/4+2(x/4+x/2)=26
解得x=8
AC=x/2=4
∵AD=DC;EM+MB.
∴(AD+DC)+CE+(EM+MB)=2DC+CE+2EM.
即AB=2(DC+CE+EM)-CE=2a-b.