Question

计算题 )(4m的平方+9n的平方)(3n-2m)(-3n-2m)=====

Answer 1

(4m^2+9n^2)(3n-2m)(-3n-2m)

=(4m^2+9n^2)(-3n+2m)(3n+2m)

=(4m^2+9n^2)(2m-3n)(2m+3n)

=(4m^2+9n^2)(4m^2-9n^2)

=(4m^2)^2-(9n^2)^2

=16m^4-81n^4

其中 x^y 表示 x的y次方

我也同意lantian1013说的浪费步骤;

五个等号太扯了...

这应该直接写答案的