Question

已知a*(x^3y^4)^3/(1/6x^2+ny^4)=3/4x^2y^2m,求实数a,m,n的值

Answer 1

a*(x^3y^4)^3/[1/6x^(2+n)y^4]=3/4x^2y^2m,

6a*(x^9y^12)/[x^(2+n)y^4]=3/4x^2y^2m,

6a* x^(9-2-n)y^(12-4)=3/4x^2y^2m,

6a* x^(7-n)y^8=3/4x^2y^2m,

∴6a=3/4,7-n=2,8=2m

∴a=1/8,m=4,n=5