计算(x-y)^5×(y-x)^2n-4÷(x-y)^2n-1÷(y-x)(x-y)^2的值
1个回答
=(x-y)^5×(x-y)^(4-2n)÷(x-y)^2n-1÷(x-y)^(-2)
=(x-y)^(5+4-2n-2n+1+2)
=(x-y)^16
=(7-5/3)^16
=(16/3)^16
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