(2x+1)/(x+2)(x-2)=A/(x+2)+B/(x-2)
A/(x+2)+B/(x-2)
=A(X-2)/(X+2)(X-2) +B(X+2)/(X+2)(X-2)
=[A(x-2)+b(x+2)]/(x+2)(x-2)
所以2x+1=A(X-2)+B(X+2)=(A+B)x-2(A-B)
所以A+B=2,-2(A-B)=1
解得:A=3/4,B=5/4
AB=15/16
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(2x+1)/(x+2)(x-2)=A/(x+2)+B/(x-2)
A/(x+2)+B/(x-2)
=A(X-2)/(X+2)(X-2) +B(X+2)/(X+2)(X-2)
=[A(x-2)+b(x+2)]/(x+2)(x-2)
所以2x+1=A(X-2)+B(X+2)=(A+B)x-2(A-B)
所以A+B=2,-2(A-B)=1
解得:A=3/4,B=5/4
AB=15/16
很高兴为您解答,【学习宝典】团队为您答题.
请点击下面的【选为满意回答】按钮,