3 个函数的参数,没用到指针,所以 它们的 实参 应当 是 初始化 （initialized）的.而 x1,x2 并 未 初始化.所以得到 这样的 信息：without being initialized. 按你的函数定义来看.你可以去掉double x1,double x2 两个...
varible is being used without being initialized
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