(1/a)-(1/b)=5
即(1/a)-(1/b)=(b-a)/ab=5
b-a=5ab
原式=2(a-b)+3ab/(a-b)-2ab
=2*(-5ab)+3ab/-5ab-2ab
=-10ab+3ab/-5ab-2ab
=-7ab/-7ab
=-1
(1/a)-(1/b)=5,则2a+3ab-2b/a-2ab-b的值为________________________
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