Question

∫1／√（e∧x）－1dx

Answer 1

令a=√(e^x-1)

x=ln(a^2+1)

dx=2ada/(a^2+1)

原式=∫1/a*2ada/(a^2+1)

=2∫da/(a^2+1)

=2arctana+C

=2arctan[√(e^x-1)]+C