Question

求导,y=(x²+1)Inx怎么做,

Answer 1

解

y‘=[(x²+1)lnx]

=(x²+1)'lnx+(x²+1)(lnx)'

=2xlnx+(x²+1)/x

=2xlnx+x+1/x

这是乘法求导

[f(x)g(x)]'=f'(x)g(x)+f(x)g'(x)