Question

已知（x-2）的平方+ 丨y+1丨=0,a,b互为相反数,c,d互为倒数,则（x+y)的x的次方+3cd-2分之1a-2

Answer 1

根据题意 x-2=0 x=2 y+1=0 y=-1 a+b=0 cd=1

（x+y)的x的次方+3cd-2分之1a-2分之1b= (2-1 )^2+3×1-1/2(a+b)

= 1+3-0

=4