=(0.5+2x2十2x4十2)xy=14.5xy
合并成同类式0.5xy+2x2y+2x4y+x2y
1个回答
相关问题
-
合并同类二次根式6√xy - 2√xy³ + 5√x³y - √x/y + √y/x (x>0,y>
-
x^2-2xy+y^2=14x^2-4xy+y^2=46x^2-5xy+y^2=0x^2-4xy+3y^2+4x-8y+
-
已知x^2+y^2-4x+6y+13=0求(xy+y^2/5x^2-5xy+xy+y^2)·(5/x+y)-(y/x-y
-
已知x^2+4y^2-4x+4y+5=0,求(x^4-y^4/2x^2+xy-y^2)*(2x-y/xy-y^2)/(x
-
合并下列各式的同类项!(1)4x²-y-8xy²+2x²y-3xy²(2)3x&
-
(-x^2+3xy-0.5y^2)-(0.5x^2+4xy-1.5y^2)=-0.5x^2+( )+y^2
-
xy-[x+2y+0.5(x-4)*(y-2)]
-
已知x^2+y^2-2x+4y+5=0.求{(x^4-y^4)/[(x+y)(2x-y)]}*{[(2x-y)/(xy-
-
已知x^2+4y^2-2x-2x+8y+5=0,求x^2-y^2/2x^2+xy-y^2*2y-y/xy-y/(x^2+
-
已知x^2+y^2-2x+4y+5=0,求(x^4-y^4)/(x^2-2xy+y^2)*(x-y