用因式分解法解方程x²-9x=0 (x-3)²+4x(x-3)=0 (3x-4)²=9x-

1个回答

  • 1.x²-9x=0

    x(x-9)=0

    x1=0 x2=9

    2.(x-3)²+4x(x-3)=0

    (x-3)(x-3+4x)=0

    (x-3)(5x-3)=0

    x1=3 x2=3/5

    3.(3x-4)²=9x-12

    (3x-4)(3x-7)=0

    x1=4/3 x2=7/3

    4.(2x+3)²-4(2x+3)+4=0

    (2x+3-2)^2=0

    2x+1=0

    x=-1/2

    适当方法解方程

    (m-3)²=5(m-3)

    m-3=5

    m=8

    4(x-1)²=9(3x+2)²

    2(x-1)=3(3x+2)

    2x-2=9x+6

    7x=-8

    x=-8/7

    49x²-14x+1=0

    (7x-1)^2=0

    7x-1=0

    x=1/7

    (x+1)²=3x+2

    x^2+2x+1=3x+2

    x^2-x=1

    (x-1/2)^2=5/4

    x-1/2=±√5/2

    x1=1/2+√5/2 x2=1/2-√5/2 .