an+1=(1/2) an +1 还是an+1=1/(2an) +1
如果是前者,用配方法
an+1 - 2 =(an - 2)/2
{an -2}是等比数列
an - 2 = ( a1-1) /2^(n-1)
an = 4*2^(-n) + 2
Sn= 4*(1/2+ 1/4+1/8+……1/2^n) + 2n
= 4*(1- 1/2^n) +2n
= 2n+4- 2^(-n)
an+1=(1/2) an +1 还是an+1=1/(2an) +1
如果是前者,用配方法
an+1 - 2 =(an - 2)/2
{an -2}是等比数列
an - 2 = ( a1-1) /2^(n-1)
an = 4*2^(-n) + 2
Sn= 4*(1/2+ 1/4+1/8+……1/2^n) + 2n
= 4*(1- 1/2^n) +2n
= 2n+4- 2^(-n)