Question

x^2-8x+13=0求(x^4-16x^3+61x^2+24x+2)/(x 62-8x+15)

Answer 1

x^2-8x+13=0

x^2-8x=-13

分子=x^4-8x^3-8x^3+61x^2+24x+2

=x^2(x^2-8x)-8x^3+61x^2+24x+2

=-13x^2-8x^3+61x^2+24x+2

=-8x^3+48x^2+24x+2

=-8x^3+64x^2-16x^2+24x+2

=-8x(x^2-8x)-16x^2+24x+2

=104x-16x^2+24x+2

=-16x^2+128x+2

=-16(x^2-8x)+2

=16*13+2

=210

分母=x^2-8x+15

=-13+15

=2

所以(x^4-16x^3+61x^2+24x+2)/(x^2-8x+15)

=210/2

=105