Question

1/2x+1/x(x-2)+1/(x-2)(x-4)+1/(x+4)(x+6)=2解方程,急

Answer 1

x-1/x+1 + x-4/x+4 =x-2/x+2 + x-3/x+3

1-2/(x+1)+1-8/(x+4)=1-4/(x+2)+1-6/(x-3)

1/(x+1)+4/(x+4)=2/(x+2)+3/(x+3)

4/(x+4)-3/(x+3)=2/(x+2)-1/(x+1)

x/(x+4)(x+3)=x/(x+1)(x+2)

x[(x^2+7x+12)-(x^2+3x+2)]=0

x(4x+10)=0

x=0或x=-5/2

经检验,符合

即得原方程的解为x=0或-5/2