原式=[(1/1)－(1/2)]＋[(1/2)－(1/3)]＋[(1/3)－(1/4)]＋…＋[(1/99)－(1/100)]
=(1/1)－(1/100)
=99/100
1/1X2+1/3X4+1/5X6+……+1/99X100=?
1个回答
相关问题
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1 1 1 1 1 ——＋——＋——＋——＋```````` —— 2X3 3X4 4X5 5X6 99X100
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1/2X1/3+1/3X1/4+1/4X1/5+1/5X1/6+.+1/99X1/100=?
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计算（1＋1.6）+（2＋1.6x2）+（3+1.6x3）+.（99+1.6x99）+（100+1.6x100）
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1x1+0x1+2x2+1x2+3x3+2x3+4x4+3x4……99x99+98x99+100x100+99x100
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[1/1x2]+[1/2x3]+[1/3x4]+[1/4x5]+…+[1/99x100]．
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[1/1x2]+[1/2x3]+[1/3x4]+[1/4x5]+…+[1/99x100]．
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[1/1x2]+[1/2x3]+[1/3x4]+[1/4x5]+…+[1/99x100]．
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1/2X3X4X5+1/3X4X5X6+1/4X5X6X7.1/97X98X99X100=?
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1X1+2X2+3X3+4X4+5X5.+98X98+99X99+100X100=?
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1/1X2+1/3X4+1/5X6+……+1/99X100=?第二项,不是1/2X3