Question

a=(根号3-根号2)(根号2-1) 求2a/(1-a^2)

Answer 1

a=(√3-√2)(√2-1)=√6-2-√3+√2

1/a=1/(√3-√2)(√2-1)=(√3+2√)(√2+1)=√6+2+√3+√2

(a^2-1)/2a

=1/2(a-1/a)

=1/2(√6-2-√3+√2-√6-2-√3-√2)

=1/2(-4-2√3)

=-2-√3

2a/(1-a^2)

=1/(-2-√3)

=(-2+√3)/(4-3)

=-2+√3