lim[(5n^2-7n^2+1)/(n-1)^2]n→∞
2个回答
5n^2-7n^2=-2n^2
lim[(5n^2-7n^2+1)/(n-1)^2]n→∞
=-2
是"lim[(5n^2-7n+1)/(n-1)^2]n→∞"的话
=5
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