Question

若实数xyz满足（x–z）^–4（x–y）（y–z）=0,xyz怎么求,

Answer 1

原等式可变为：

(x-y+y-z)^2-4(x-y)(y-z)=0 =>(x-y)^2+2(x-y)(y-z)-4(x-y)(y-z)+(y-z)^2=0

=>(x-y-y+z)^2=0 由实数平方大于等于0可知：x+z=2y

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