2x^2+3xy-2y^2=0
(2x-y)(x+2y)=0
y=2x或x=-2y
当y=2x时
(3x^2+4xy+5y^2)/(x^2-y^2)
=[3x^2+4x*2x+5*(2x)^2]/[x^2-(2x)^2]
=[3x^2+8x^2+20x^2]/[x^2-4x^2]
=(31x^2)/(-3x^2)
=-31/3
当x=-2y时
(3x^2+4xy+5y^2)/(x^2-y^2)
=[3*(-2y)^2+4*(-2y)*y+5*y^2]/[(-2y)^2-y^2]
=[12y^2-8y^2+5y^2]/[4y^2-y^2]
=(9y^2)/(3y^2)
=3