Question

规定一种运算符号"#"的意义是：a#b=(a+b)的平方-ab+a/b,已知：|2x-1|+（y+2的平方=0,试求x#

Answer 1

∵|2x-1|≧0;(y+2)²≧0;且它们的和等于0 ∴2x-1=0 ; y+2=0 => x=1/2; y=-2

∴x#y=(1/2)#(-2)=(1/2-2)²-(-2)/2+(1/2)/(-2)

=9/4+1-1/4

=3