J(a,b)f(x)dx为函数f(x)从[a,b]的积分,pi为圆周率
sinx 在[0,1]之间,当x在[0,pi]之间 所以f(sinx)在[0,pi]之间连续,因此,f(sinx)在[0,pi]上可积.
同理可证f(cosx)在[0,pi/2]上可积.
xf(sinx)在[0,pi]上连续,因此xf(sinx)也可积.
1.令x = pi/2 - t
J(0,pi/2) f(sinx) dx = J(pi/2,0) f(sin(pi/2 - t)) d(pi/2 - t) = J(pi/2,0) f(cos t) -1 dt
= J(0,pi/2)f(cost)dt = J(0,pi/2)f(cosx)dx
2.令x = pi - t,则
J(0,pi) xf(sinx) dx = J(pi,0) (pi - t)f(sin(pi - t))d(pi - t) = J(pi,0) (pi - t)f(sint) -dt
= J(0,pi) (pi - t)f(sint)dt = J(0,pi) pi * sint dt - J(0,pi) t sint dt
=pi * J(0,pi) sinx dx - J(0,pi) x sinx dx
将等式右边 J(0,pi) x sinx dx,移到左边可得
2 J(0,pi) x sinx dx = pi * J(0,pi) sinx dx
J(0,pi) x sinx dx = pi/2 * J(0,pi) sinx dx