1/2(1-x)=1+k
1-x=2(1+k)=2+2k
x=-2k-1
4/3(3x+2)=10k-2/3(x-1)
3x+2=3/4[10k-2/3(x-1)]
3x+2=15k/2-1/2(x-1)
6x+4=15k-(x-1)
7x=15k-3
x=15k/7-3/7
所以15k/7-3/7=-(-2k-1)=2k+1
15k-3=14k+7
k=10
1/2(1-x)=1+k
1-x=2(1+k)=2+2k
x=-2k-1
4/3(3x+2)=10k-2/3(x-1)
3x+2=3/4[10k-2/3(x-1)]
3x+2=15k/2-1/2(x-1)
6x+4=15k-(x-1)
7x=15k-3
x=15k/7-3/7
所以15k/7-3/7=-(-2k-1)=2k+1
15k-3=14k+7
k=10