1,当n=1时命题成立
2,假设n=k时命题成立,即9^(k+2)-4^k = 5m,m属于整数,
当n=k+1时,9^(k+3)-4^(k+1)=9*9^(k+2)-4*4^k=(5+4)*9^(k+2)-4*4^k=5*9^(k+2)+4*9^(k+2)-4*4^k
=5*9^(k+2)+4*(9^(k+2)-4^k)=5*9^(k+2)+4*5m,整除5
由1,2可知命题成立
1,当n=1时命题成立
2,假设n=k时命题成立,即9^(k+2)-4^k = 5m,m属于整数,
当n=k+1时,9^(k+3)-4^(k+1)=9*9^(k+2)-4*4^k=(5+4)*9^(k+2)-4*4^k=5*9^(k+2)+4*9^(k+2)-4*4^k
=5*9^(k+2)+4*(9^(k+2)-4^k)=5*9^(k+2)+4*5m,整除5
由1,2可知命题成立