72
如图,△ABC中,AB=AC,BD平分∠ABC,交AC于D.若∠ABD=36°,则∠BDC=( &
1个回答
相关问题
-
如图,△ABC中,AB=AC,BD平分∠ABC交AC于点D,若∠A=52°,则∠BDC等于( )
-
如图,在△ABC中,AB=AC,∠A=36°,BD平分∠ABC交AC于点D,DE平分∠BDC交BC于点E,则[EC/AD
-
如图,△ABC中,AB=AC,∠A=36°,BD平分∠ABC交AC于点D,DE∥AB交BC于E,EF∥BD交CD于F,则
-
如图,△ABC中,AB=AC,∠A=36°,AB的垂直平分线DE交AC于D,交AB于E,则∠BDC的度数为 [
-
△ABC中,AB=AC,BD平分∠ABC交AC边于点D,∠BDC=75°,则∠A的度数为______.
-
△ABC中,AB=AC,BD平分∠ABC交AC边于点D,∠BDC=75°,则∠A的度数为______.
-
△ABC中,AB=AC,BD平分∠ABC交AC边于点D,∠BDC=75°,则∠A的度数为______.
-
如图,在△ABC中,AB=AC,∠A=36°,AB的中垂线DE交AC于D,交AB于E,(1)BD平分∠ABC;(2)点D
-
如图,△ABC中,AB=AC,∠A=36°,AB的垂直平分线DE交AC于D,交AB于E,下述结论:(1)BD平分∠ABC
-
如图,△ABC中,AB=AC,∠A=36°,AB的中垂线DE交AC于D,交AB于E,下述结论:(1)BD平分∠ABC;(