设c点坐标为(x,y)
则E点坐标为(x2,(y+1)2)
则D点坐标为(x-3,y+1)
带入函数y=kx
(y+1)2*x2=k (y+1)*x=4k
(y+1)*(x-3)=k
所以
(x-3)x=0.25
x=4
又x*y=k
(y+1)*1=4*y
y=13
设c点坐标为(x,y)
则E点坐标为(x2,(y+1)2)
则D点坐标为(x-3,y+1)
带入函数y=kx
(y+1)2*x2=k (y+1)*x=4k
(y+1)*(x-3)=k
所以
(x-3)x=0.25
x=4
又x*y=k
(y+1)*1=4*y
y=13