已知sin(π-α)=-1/2,计算:(1)cos(3π+α) (2)tan(5π-α)
3个回答
sin(π-α)=sinα=-1/2,
cos(3π+α)=cos(π+α)=-cosα=根号3/2或-根号3/2
tan(5π-α)=tan(π-α)=-tanα=根号3/3或-根号3/3
相关问题
已知:sin(π+α)=-1/2 计算:sin(π/2+α) cos(α-3π/2) tan(π/2-α)
已知f(α)=sin(π-α)cos(2π-α)tan(-α+3π/2)tan(-α-π) /sin(-π-α).(1)
已知:f(α)=sin(π2−α)•cos(3π2−α)•tan(5π+α)tan(−α−π)•sin(α−3π)
已知f(α)=sin2(π−α)•cos(2π−α)•tan(−π+α)sin(−π+α)•tan(−α+3π).
已知f(α)=sin2(π−α)•cos(2π−α)•tan(−π+α)sin(π+α)•tan(−α+3π),
已知f(α)=sin(α−π2)cos(3π2−α)tan(2π−α)tan(−α−π)sin(π+α).
已知sinα=1/9,求[cos(α-5π)tan(2π-α)/cos(3π/2 +α)]+tan²α 值
已知tan(3π+α)=3,求(1)sin(α−3π)+cos(π−α)+sin(π2−α)−2cos(π2+α)−si
已知cos(π+α)=-1/2 计算sin(2π+α)-tan(α-3π)的值
已知sin(π+α)=-1/2 计算 1.cos(2π-α) 2.tan(α-7π)