2x-x^3=(x-2)(2-3x^2)求解x
1个回答
2x-x^3=(x-2)(2-3x^2)
= 2x-3x^3-4 + 6x^2
2x^3-6x^2+4=0
2(x-1)(x^2-2x -2)=0
x=1 or 1+√3 or 1-√3
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