tan(41π/6)=-根号3/3怎么算出来的?c - 知识问答

tan(41π/6)=-根号3/3怎么算出来的?cos（π/4-4π）又怎么算

2个回答

tan(41π/6)
=tan(3*2π + 5π/6)
=tan( 5π/6)
=tan(π-π/6)
=-tanπ/6
=-根号3/3
cos（π/4-4π）
=cos[-(4π-π/4)]
=cos(4π-π/4)
=cos(-π/4)
=cos(π/4)
=根号2/2

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