Question

1、减去-3X得X的2次方-3X+6的式子为————————

Answer 1

-3X+(X²-3X+6)=X²-6X+6 答案是 X²-6X+6

(a^4-b^4)/(a²-b²)=(a²+b²)(a²-b²)/(a²-b²)=(a²+b²) 答案是 a²+b²

()=(12a^4-12a^3+4a²)÷(-4a²)=-3a²+3a-1 答案是 -3a²+3a-1

4 题目有点不清晰