Question

计算 (a^2b-ab-a+1)/(ab^2+3ab-b-3)÷(a^2+a_2)/(b^2+b-6)

Answer 1

原式=(ab(a-1) - (a-1)) / (ab(b+3) - (b+3)) ÷ ((a+2)(a-1))/((b+3)(b-2))

= (a-1)/(b+3) * ((b+3)(b-2))/((a+2)(a-1))

=(b-2)/(a+2)