lim[x(ln(a+bx)]/sin(ax^2)(x趋于0)
=lim[x(ln(a+bx)]/(ax^2)(x趋于0)
=limln(a+bx)/(ax)
所以limln(a+bx)=0
所以a=1
lim[x(ln(a+bx)]/sin(ax^2)(x趋于0)
=limln(1+bx)/x
=lim(bx)/x
=b
题目输完了吗?x趋于多少?求极限还是求a,b?
lim[x(ln(a+bx)]/sin(ax^2)(x趋于0)
=lim[x(ln(a+bx)]/(ax^2)(x趋于0)
=limln(a+bx)/(ax)
所以limln(a+bx)=0
所以a=1
lim[x(ln(a+bx)]/sin(ax^2)(x趋于0)
=limln(1+bx)/x
=lim(bx)/x
=b
题目输完了吗?x趋于多少?求极限还是求a,b?