Question

把下列各式分解因式.1.a的(n+2)次方 +a的(n+1)次方再乘以b 减去 6a的n次方乘以b的2次方.2.x的4次

Answer 1

a^(n+2)+a^(n+1)b-6a^nb^2=a^n*(a^2+ab-6b^2)=a^n*(a+3b)(a-2b)x^4-7x^2-18=(x^2-9)(x^2+2)=(x+3)(x-3)(x^2+2)(6x^2-7x)^2-25=(6x^2-7x+5)(6x^2-7x-5)=(6x^2-7x+5)(3x-5)(2x+1)