∵AD∥BC,
∴∠DAC=∠ACB,
又∵∠DCA=∠ACB,
∴∠DAC=∠DCA,
∴AD=CD,
又∵AB=CD,
∴AB=CD=AD,
又∵AB+BC+CD+DA=4.5,BC=1.5,
∴上底=CD=1 CM