(1)
1/√2+1=(√2-1)/(√2+1)(√2-1)=√2-1,
1/(√3+√2)=(√3-√2)/(√3+√2)(√3-√2)=√3-√2
.
1/(√2009+√2008)=(√2009-√2008)/(√2009+√2008)(√2009-√2008)=√2009-√2008
所以 原式=(√2009-1)(√2009+1)=2009-1=2008
(2)
3/(4-√13)=3(4+√13)/(4-√13)(4+√13)=3(4+√13)/3=4+√13
同理 6/(√13-√7)=√13+√7 2/(3+√7)=3-√7
所以 原式=4-3=1