Question

设A为3阶方阵,B为4阶方阵,且行列式|A|=1,|B|=-2,则行列式||B|A|的值,答案是：-8急求过程,

Answer 1

||B|A|

= |B|^3 |A|

= (-2)^3 * 1

= -8.

知识点: |kA| = k^n|A|