Question

计算a²/(a²-2ab)×√(a²b-4ab²+4b^3)/a+b√(a/b)

Answer 1

原式=a/(a-2b)×√b(a-2b)²/a+b√(a/b)

=a/(a-2b)×(2b-a)√b/a+b√a/b

=-a√b/a+b√a/b

=-√ab+√ab=0

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