Question

程序设计 用求根公式求一元二次方程x^2+3x+2=0的解.

Answer 1

python

import math

a=1.0

b=3.0

c=2.0

x1 = (-b + math.sqrt(b**2-4*a*c))/(2*a)

x2 = (-b - math.sqrt(b**2-4*a*c))/(2*a)