知1+tan(θ+720°) / 1-tan(θ-360°) = 3+2根号2 求
[cos^2(π-θ)+sin(π+θ)*cos(π-θ)+2sin^2(θ-π)]* 1/cos^2(-θ-2π)的值
由已知得:(1+tanθ)/(1-tanθ)=3+2根号2,
tanθ=根号2/2
原式=[cos^2(θ)+sinθcosθ+2sin^2(θ)]/cos^2(θ)
=1+tanθ+2tan^2(θ)
=1+根号2/2+1
=2+根号2/2
(1+tanα)/(1-tanα)=3+2√2,求cos^2(π-α)+sin(π+α)*cos(π-α)+2sin(α
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